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8c^2-41c-42=0
a = 8; b = -41; c = -42;
Δ = b2-4ac
Δ = -412-4·8·(-42)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-55}{2*8}=\frac{-14}{16} =-7/8 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+55}{2*8}=\frac{96}{16} =6 $
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